A catapult launches a boulder with an upward velocity of 184 ft/s. The height of the boulder (h) in feet after t seconds is given by the function h= -16t^2 + 184t + 20. How long does it take the boulder to reach its maximum height? What is the boulder's maximum hieght
Accepted Solution
A:
For this case we have the following equation: h = -16t ^ 2 + 184t + 20 Deriving we have: h '= -32t + 184 We equal zero and clear t: -32t + 184 = 0 32t = 184 t = 184/32 t = 5.75 s Then, the maximum height is given by: h (5.75) = -16 * (5.75) ^ 2 + 184 * (5.75) + 20 h (5.75) = 549 feet Answer: It takes the boulder to reach its maximum height about: t = 5.75 s the boulder's maximum hieght is: h (5.75) = 549 feet