please help. how much would the statue weigh if the original was 10feet?

Answer:Part a) The weight of the original statue is [tex]9,483\ pounds[/tex]The ratio of the height of the original statue to the height of the small statue is 8.4The ratio of the weights or volumes is [tex]8.4^{3}[/tex]Part b)  [tex]221,184\ pounds[/tex]Step-by-step explanation:Part a) we know thatIf two figures are similar, then the ratio of its corresponding sides is equal to the scale factor and the ratio of its volumes or weights is equal to the scale factor elevated to the cubestep 1Find the scale factorremember that[tex]1\ ft=12\ in[/tex]The original statue is 7 ft tallConvert to inches[tex]7\ ft=7*12=84\ in[/tex]Divide the height of the original statue by the height of the model to find the scale factor[tex]\frac{84}{10}=8.4[/tex]step 2Find the ratio of its weightsLetz-----> the scale factorx-----> the weight of the original statuey----> the weight of the modelso[tex]z^{3}=\frac{x}{y}[/tex]we have[tex]z=8.4[/tex][tex]y=16\ lb[/tex]substitute[tex]8.4^{3}=\frac{x}{16}[/tex][tex]x=16(8.4^{3})=9,483\ pounds[/tex]The weight of the original statue is [tex]9,483\ pounds[/tex]The ratio of the height of the original statue to the height of the small statue is 8.4The ratio of the weights or volumes is [tex]8.4^{3}[/tex]Part b) If the original statue were 20 ft tall, how much would it weight?step 1Find the scale factorremember that[tex]1\ ft=12\ in[/tex]The original statue is 20 ft tallConvert to inches[tex]20\ ft=20*12=240\ in[/tex]Divide the height of the original statue by the height of the model to find the scale factor[tex]\frac{240}{10}=24[/tex]step 2Find the ratio of its weightsLetz-----> the scale factorx-----> the weight of the original statuey----> the weight of the modelso[tex]z^{3}=\frac{x}{y}[/tex]we have[tex]z=24[/tex][tex]y=16\ lb[/tex]substitute[tex]24^{3}=\frac{x}{16}[/tex][tex]x=16(24^{3})=221,184\ pounds[/tex]